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reeseo3o
approved these changes
Mar 7, 2026
reeseo3o
approved these changes
Mar 7, 2026
| public boolean containsDuplicate(int[] nums) { | ||
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| for(int i=0; i<nums.length; i++){ | ||
| if (!save.contains(nums[i])) save.add(nums[i]); |
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여기서는 Set.add의 반환값을 활용해서
if (!save.add(nums[i])) return true;
처럼 한 줄로 줄여볼 수도 있을 것 같습니다!
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set의 add를 통해 한 줄로 줄여볼 수도 있네요! 조언 감사합니다
| class Solution { | ||
| static int[] answer = new int[2]; | ||
| public int[] twoSum(int[] nums, int target) { | ||
| Map<Integer, Integer> maps = new HashMap<>();//num , index |
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HashMap을 사용해서 {값 -> 인덱스}를 저장해 두고 한 번의 순회로 정답을 찾는 방식이라 시간 복잡도가 O(n)으로 잘 설계된 풀이로 보입니다!
특히 int t = target - nums[i];로 필요한 값을 계산해 두고 containsKey로 바로 확인하는 흐름이 깔끔하고 좋은 것 같습니다! 👍
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