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4 changes: 4 additions & 0 deletions contains-duplicate/dongzoolee.ts
Original file line number Diff line number Diff line change
@@ -0,0 +1,4 @@
function containsDuplicate(nums: number[]): boolean {
const sets = new Set<number>(nums);
return sets.size < nums.length;
}
17 changes: 17 additions & 0 deletions longest-consecutive-sequence/dongzoolee.ts
Original file line number Diff line number Diff line change
@@ -0,0 +1,17 @@
function longestConsecutive(nums: number[]): number {
const st = new Set(nums);

let mx = 0;
for (const n of st) {
if (st.has(n - 1)) continue;

let len = 1;
while (st.has(n + len)) {
len++;
}

mx = Math.max(mx, len);
}

return mx;
}
15 changes: 15 additions & 0 deletions top-k-frequent-elements/dongzoolee.ts
Original file line number Diff line number Diff line change
@@ -0,0 +1,15 @@
function topKFrequent(nums: number[], k: number): number[] {
const mp: { [k: number]: number } = {};
nums.forEach((n) => (typeof mp[n] === "number" ? mp[n]++ : (mp[n] = 1)));

const unq_nums = [...new Set(nums)];
unq_nums.sort((a, b) => {
if (mp[a] === mp[b]) {
return 0;
}

return mp[a] < mp[b] ? 1 : -1;
});
Comment on lines +6 to +12
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여기 부분을 unq_nums.sort((a, b) => mp[b] - mp[a]);
이런시으로 단순화 할수있을것 같습니다.


return unq_nums.slice(0, k);
}
20 changes: 20 additions & 0 deletions two-sum/dongzoolee.ts
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l,r 같이 포인터를 이용해서 조합을 순회하는 방식으로 구현하신 것 같은데, 이런 구조를 선택하신 이유가 있을까요?
모든 쌍을 확인하는 문제라서 이중 for문이 의도를 파악하기에는 더 쉬울 것 같다는 생각이 들었습니다.

Original file line number Diff line number Diff line change
@@ -0,0 +1,20 @@
function twoSum(nums: number[], target: number): number[] {
const sz = nums.length;
let l = 0,
r = 1,
sm = nums[0] + nums[1];

while (l <= sz - 2 && r <= sz - 1) {
sm = nums[l] + nums[r];

if (sm === target) {
return [l, r];
}

if (l === r - 1) {
(r++, (l = 0));
} else {
l++;
}
}
}