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maximum_subarray.py
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49 lines (36 loc) · 1.22 KB
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"""
https://leetcode.com/problems/maximum-subarray/description/
Given an integer array nums, find the subarray with the largest sum, and return its sum.
Example 1:
Input: nums = [-2,1,-3,4,-1,2,1,-5,4]
Output: 6
Explanation: The subarray [4,-1,2,1] has the largest sum 6.
Example 2:
Input: nums = [1]
Output: 1
Explanation: The subarray [1] has the largest sum 1.
Example 3:
Input: nums = [5,4,-1,7,8]
Output: 23
Explanation: The subarray [5,4,-1,7,8] has the largest sum 23.
Constraints:
1 <= nums.length <= 105
-104 <= nums[i] <= 104
Follow up: If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle.
"""
from typing import List
def max_sub_array(nums: List[int]) -> int:
largest_sum = float('-inf')
current_sum = 0
has_reached_zero = False
for num in nums:
if current_sum + num < 0:
current_sum = num
else:
current_sum += num
if not has_reached_zero and current_sum >= 0:
has_reached_zero = True
if has_reached_zero:
current_sum = max(0, current_sum)
largest_sum = max(largest_sum, current_sum)
return largest_sum