002-PROGRAM-TO-FIND-SQUARE-ROOT-OF-A-NUMBER-IN-PYTHON

[atharvaagrawal]

Input:

Enter any number: 16

Output:

Number: 4.0

[Pranjal-Sancheti]

import math
no = float(input("Enter any number: "))
squareroot = math.sqrt(no)
print("Number: ",squareroot)

[Libin-Lijo]

n=float(input("enter a number"))
Sqrt=n**(1/2)
Print("number: ,sqrt)

[megsameghana]

n=float(input("enter an number"))
if n<0:
print("enter an valid number")
else
sqrt=n**0.5
print("number:",sqrt)