Patients_With_Condition.sql

-- Table: Patients

-- +--------------+---------+
-- | Column Name  | Type    |
-- +--------------+---------+
-- | patient_id   | int     |
-- | patient_name | varchar |
-- | conditions   | varchar |
-- +--------------+---------+
-- patient_id is the primary key (column with unique values) for this table.
-- 'conditions' contains 0 or more code separated by spaces. 
-- This table contains information of the patients in the hospital.
 

-- Write a solution to find the patient_id, patient_name, and conditions of the patients who have Type I Diabetes. Type I Diabetes always starts with DIAB1 prefix.

-- Return the result table in any order.

-- The result format is in the following example.

 

-- Example 1:

-- Input: 
-- Patients table:
-- +------------+--------------+--------------+
-- | patient_id | patient_name | conditions   |
-- +------------+--------------+--------------+
-- | 1          | Daniel       | YFEV COUGH   |
-- | 2          | Alice        |              |
-- | 3          | Bob          | DIAB100 MYOP |
-- | 4          | George       | ACNE DIAB100 |
-- | 5          | Alain        | DIAB201      |
-- +------------+--------------+--------------+
-- Output: 
-- +------------+--------------+--------------+
-- | patient_id | patient_name | conditions   |
-- +------------+--------------+--------------+
-- | 3          | Bob          | DIAB100 MYOP |
-- | 4          | George       | ACNE DIAB100 | 
-- +------------+--------------+--------------+
-- Explanation: Bob and George both have a condition that starts with DIAB1.

-- Solution
-- Write your PostgreSQL query statement below
select patient_id,
       patient_name,
       conditions
from Patients 
where LOWER(conditions) like LOWER('DIAB1%') or 
      LOWER(conditions) like LOWER('% DIAB1%');